72 Views

formula to find percentile?give example


ram aniruth 29th Jul, 2021
Answer (1)
Akash Singh 29th Jul, 2021

Dear student,

First of all understand what is the purpose of percentile.

So, percentile tell us where a person is standing in a competition. Like how many students are there who are below him/her in the exam.

The formula for percentile is below.

Percentile = (Number of Values Below “x” / Total Number of Values) × 100

Now let us suppose, in an exam, 10 students participated and the scores of these 10 students are given below.

20, 10, 30, 50, 40, 60, 70, 80, 100, 90 respectively.

Now if the guy who scored 70 marks asked his percentile then,

First of all find 'x' which is how many students are there who scored less than him. To so this arrange the marks in ascending order.

10, 20, 30, 40, 50, 60, 70, 80, 90, 100

So from here we can say x = 6

Now Total number of values = 10

Percentile of 70 marks guy = (6/10)*100 = 60

So the guy who scored 70 marks has 60 percentile.

I hope it clarifies your doubts.

All the very best!!

Related Questions

UPES Integrated LLB Admission...
Apply
Ranked #28 amongst Institutions in India by NIRF | Ranked #1 in India for Academic Reputation by QS University Rankings | 16.6 LPA Highest CTC
Jindal Global Law School Admi...
Apply
Ranked #1 Law School in India & South Asia by QS- World University Rankings | Merit cum means scholarships | Application Deadline: 30th Nov'24
Chandigarh University Admissi...
Apply
Ranked #1 Among all Private Indian Universities In QS Asia Rankings 2025 | Scholarships worth 210 CR
Great Lakes PGPM & PGDM 2025
Apply
Admissions Open | Globally Recognized by AACSB (US) & AMBA (UK) | 17.3 LPA Avg. CTC for PGPM 2024 | Application Deadline: 1st Dec 2024
ICFAI Business School-IBSAT 2024
Apply
9 IBS Campuses | Scholarships Worth Rs 10 CR
Nirma University Law Admissio...
Apply
Grade 'A+' accredited by NAAC
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books