f(x)=x^2+1/x^2 then find the value of f(x)
Answers (2)
11th Mar, 2021
I believe the questions suggests, to find when f(x)is maximum or minimum.
Hence we first differentiate the expression.
f'(x)= 2x-2x^-3
On equating f'(x)=0, we get 4 solutions (+/-)i and (+/-)1.
Hence by using Hit and Trial Method we determine, f(x) is maximum for +1,-1 and mininum for +i,-i.
Hence, f(x) maximum will be 2 and minimum will be -2.
Comments (0)
11th Mar, 2021
Hello candidate,
The meaning of this term f'(x) refers to the first derivative of the Function with respect to X.
f(x)=x^2+1/x^2 is the function given, so the value of f'(x) is given as 2x -2/x^3, as the formula for d/dx (x^n)= nx^n-1 is used to solve the above equation.
Hope this answer was helpful!!
Good luck.
Comments (0)
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