getting cs in nit Warangal or getting cs in iiit Hyderabad is easier pls tell me minimum marks to get cs in both clg??
Answer (1)
Hello there,
You haven't mentioned your category and home state. I'm assuming that you are from the general category. The cutoff rank for NIT Warangal and IIIT Hyderabad are nearly same. Analysing the previous year data, the cutoff ranks for CS were:
NIT Warangal:
2977 under Home State quota
1980 for other states
You can check the link given below for more information about the same:
https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-warangal
IIIT Hyderabad:
1059 in the year 2019
You can check the link given below for more information about the same:
https://engineering.careers360.com/articles/iiit-hyderabad-btech-cutoff
For getting this rank, you need to score 99+ percentile in your JEE Main. A score of 180+ will fetch you this percentile and rank.
You can use our rank predictor to get an idea of your target marks:
Also note that the cut-off rank changes every year depending on the difficulty of the paper, and the number of candidates appearing for it.
Hope this answer helps you.
Good luck!!
You haven't mentioned your category and home state. I'm assuming that you are from the general category. The cutoff rank for NIT Warangal and IIIT Hyderabad are nearly same. Analysing the previous year data, the cutoff ranks for CS were:
NIT Warangal:
2977 under Home State quota
1980 for other states
You can check the link given below for more information about the same:
https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-warangal
IIIT Hyderabad:
1059 in the year 2019
You can check the link given below for more information about the same:
https://engineering.careers360.com/articles/iiit-hyderabad-btech-cutoff
For getting this rank, you need to score 99+ percentile in your JEE Main. A score of 180+ will fetch you this percentile and rank.
You can use our rank predictor to get an idea of your target marks:
Also note that the cut-off rank changes every year depending on the difficulty of the paper, and the number of candidates appearing for it.
Hope this answer helps you.
Good luck!!
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