Given that the displacement of an oscillating particle is given by y=A sin (Bx + Ct + D). The dimensional formula for (ABCD) is
Answer (1)
23rd Apr, 2020
Hey,
Every term which is written inside the sin is dimensionless, thus:
Bx= M^0 L^0 T^0
which means
B= M^0 L^-1 T^0
Lt= M^0 L^0 T^0
C=M^0 L^0 T^-1
D=M^0 L^0 T^0
A=M^0 L^1 T^0
Therefore,
the dimensional formula of ABCD is
=(L^1 L^-1 T^-1)*(M^0 L^0 T^0) = M^0 L^0 T^-1
which is the required answer.
I hope this helps.
All the best!
Comments (0)
