2657 Views

Given that the displacement of an oscillating particle is given by y=A sin (Bx + Ct + D). The dimensional formula for (ABCD) is


kishorereddy07205 23rd Apr, 2020
Answer (1)
Smrity 23rd Apr, 2020

Hey,

Every term which is written inside the sin is dimensionless, thus:

Bx= M^0 L^0 T^0

which means

B= M^0 L^-1 T^0

Lt= M^0 L^0 T^0

C=M^0 L^0 T^-1

D=M^0 L^0 T^0

A=M^0 L^1 T^0

Therefore,

the dimensional formula of ABCD  is

=(L^1 L^-1 T^-1)*(M^0 L^0 T^0) = M^0 L^0 T^-1

which is the required answer.

I hope this helps.

All the best!

Related Questions

East Point College | BBA Admi...
Apply
NBA Accredited | AICTE Approved
TAPMI MBA 2025 | Technology M...
Apply
MBA Admission Open in Technology Management and AI & Data Science | NAAC A++ | Institution of Eminence | Assured Scholarships
Amity University, Noida Law A...
Apply
700+ Campus placements at top national and global law firms, corporates, and judiciaries
East Point College | MBA Admi...
Apply
NBA Accredited | AICTE Approved
Chitkara University MBA Admis...
Apply
NAAC A+ Accredited | 100% CAMPUS RECRUITMENT
Amrita Vishwa Vidyapeetham | ...
Apply
Recognized as Institute of Eminence by Govt. of India | NAAC ‘A++’ Grade | Upto 75% Scholarships | Extended Application Deadline: 30th Jan
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books