Question : Half of the length of a chord of a circle is 12 cm and the perpendicular distance between the centre and the chord is 5 cm. The radius of the circle is:
Option 1: 12 cm
Option 2: 13 cm
Option 3: 10 cm
Option 4: 24 cm
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Correct Answer: 13 cm
Solution : Here, the radius of the circle is OA. AD is half the length of the chord, AB. AD = 12 cm OD = 5 cm Using Pythagoras theorem we get, OA 2 = OD 2 + AD 2 ⇒ OA = $\sqrt{5^2+12^2}=13$ cm Hence, the correct answer is 13 cm.
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