Question : H.C.F of $\frac{2}{3},\frac{4}{5}$ and $\frac{6}{7}$ is:
Option 1: $\frac{48}{105}$
Option 2: $\frac{2}{105}$
Option 3: $\frac{1}{105}$
Option 4: $\frac{24}{105}$
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Correct Answer: $\frac{2}{105}$
Solution : Given: $\frac{2}{3},\frac{4}{5},\frac{6}{7}$ Apply formula, HCF of the fraction = $\frac{\text{HCF of numerator}}{\text{LCM of denominator}}$ HCF of 2, 4, and 6 is 2. LCM of 3, 5, and 7 is 105. Hence, the correct answer is $\frac{2}{105}$.
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