Hello,
The volume of the right circular cone is V= (1/3)*Pi*r^2*h
The new increased height of the cone can be written as (120/100)*h
The new increased based radius of the cone can be written as (110/100)*r
Now the new volume is= (1/3)*Pi*(1.1r)^2*(1.2h) = 1.452*((Pi*r^2*h)/3) which is also equal to 1.452*V
So the change in volume is ((1.452*100)-100)= 145.2-100= 45.2%
Question : Which of the following statements is not correct?
Question : If the radius of the base, and the height of a right circular cone are increased by 20%, what is the approximate percentage increase in volume?
Question : A right circular cone is 3.6 cm high, and the radius of its base is 1.6 cm. It is melted and recast into a right circular cone with a radius of 1.2 cm at its base. Then the height of the cone (in cm) is:
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