Hello Sir I got 146 marks in 29 july shift 1 2022 JEE Mains Exam OBC category. Can I get CSE in any NIT .
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Hi
With 146 marks
-
Your percentile will be roughly around 97.17 - 98.57 , considering paper of moderate level and considering the worst case if we go with 97.17 percentile then your rank would be roughly around 6k obc rank
Now,
This is difficult to predict the college as cut off keeps changing every year depending upon various factors
-
like number of students that appeared in the exam, kind of marks obtained by them ,
-
toughness level of the jee main examination ,
-
number of seats available for the different branch
The category you belong to etc.
But yes,
When we go through previous year trend then ,
Some of the best colleges for your rank in which you have chances are listed below along with their closing rank in 6th round of josaa counselling 2020 under other state -
---------) National Institute of Technology, trichy :-Metallurgical and Materials Engineering :- 6908 obc rank
-----------) National Institute of Technology, Jalandhar, Mechanical Engineering:- 7953 obc rank
-----------) National Institute of Technology, Tiruchirappalli:- Production Engineering:- 7496 obc rank
-----------) National Institute of Technology, Srinagar:- CSE :-7593 obc rank
-----------) National Institute of Technology, Manipur:- computer science :-8349 obc rank
And more
So, yes you can definitely get a seat for computer science in NITs
You can check the closing ranks at official website of josaa by going through the link given below
JOSAA :- https://josaa.nic.in/Counseling/seatallotmentresult/currentorcr.aspx
Above prediction has been made considering past year cut off data but closing rank for colleges varies every year depending upon many factors like jee main question paper difficulty, number of students writing the exam etc so
To help you get the complete list of colleges that you can get on the basis of the category you belong to, your home state, your gender etc, we have JEE main college predictor ,the link for which is provided below:-
https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer
To help you further,
To give an idea of jee main 2022 qualifying cut off to be eligible for jee advanced 2022.
Minimum percentile in jee main 2021 to qualify it to be eligible for jee advanced 2021 is given below :-
--------) general :-87.8992241 percentile
--------) EWS:- 66.2214845 percentile
--------) OBC-NCL :- 68.0234447 percentile
--------) SC :- 46.8825338 percentile
--------) ST:- 34.6728999 percentile
--------) PWD :- 0.0096375 percentile
You can check the same at our page the link is provided below
https://engineering.careers360.com/articles/jee-main-cutoff
Best Regards
ADITYA KUMAR
Dear aspirant hope you are doing well. It's difficult to predict because cut keep changing every year depends on various factors.
1. No of seat available.
2. Difficulty level of exam.
3. No of student appear in exam.
As you scored in 146 in jee main 2022 . You rank will lie in between 21145-16495 . You can also check out the same using the link given below.
https://engineering.careers360.com/articles/jee-main-marks-vs-percentile
According to pervious years cut off you have chances of getting these college
- NIT Agartala
- NIT Srinagar
- NITs CSE cut off college wise..
https://engineering.careers360.com/articles/nits-cutoff-for-b-tech-computer-science-and-engineering
To know the list of engineering colleges , you have chances to get admission, you can also use JEE MAINS college predictor tool. Link is given below..
https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer
Pervious years percentile to qualify the jee advance is given
- General : -87.8992241 percentile
- EWS:- 66.2214845 percentile
- OBC-NCL :- 68.0234447 percentile
- SC :- 46.8825338 percentile
- ST:- 34.6728999 percentile
- PWD :- 0.0096375 percentile
you can use this cut off as a reference for jee advance 2022.
you can also check the same using the link given below..
https://engineering.careers360.com/articles/jee-main-cutoff
Hope it's helpful..
Thank you
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