Hello Sirs - I scored 93.7217757 in my JEE Main PAPER II. What is my ranking ? And what is my ranking under OBC Category ?

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Hello Sirs - I scored 93.7217757 in my JEE Main PAPER II. What is my ranking ? And what is my ranking under OBC Category ?

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Monish G S 1st Feb, 2019

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Akshay kumar 1st Feb, 2019

Hello aspirant,

Thanks for contacting careers360.

It is not possible to find the approximate rank.better wait for the official result to be declared by national testing agency nta in april.if you want to find the approximate rank use this formula Rank(approximate)=(100-NTA score)*(number of students appeared)÷100

In case of any more queries feel free to ask.thank you!

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Monish G S

1st Feb, 2019

What are possibility of getting admission in B Arch. (NIT Trichy). I belong to OBC.

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dhameerbhatia31_7970609 Student Expert 1st Feb, 2019

Hello Manish G S,

You can use the formulae given below to claculate your rank -

Rank Formula = (100 - your total score) X 145386 /100.

145386 are the number of candidates who appeared for Examination.

All the best!

Thanku.

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Pawan Kumar Patel

1st Feb, 2019

Please u can tell me about how many questions right in every sections because I am not satisfied with my aptitude percentile

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Monish G S

1st Feb, 2019

What are possibility of getting admission in B Arch. (NIT Trichy). I belong to OBC.

Reply

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