hey .. i got 87.462 percentile in paper2 and my cate. is OBC
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Answer (1)
14th Feb, 2019
It would be difficult to provide you the exact information as JEE Main is being conducted twice by NTA for the first time and rank will be announced in the month of April after both of the session January & April.
As a total Candidates 1,45,836 appeared for JEE Main paper II. Using the formula (100-your score)*1,45,386/100.
Your probable rank will be 18,900. The chances seems less to get a seat in NITs.
You can check teh previous year cutoff with the given below link.
https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning
This is only the prediction about the rank, The actual rank will be announced in the month of April.
Good Luck!
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