hi can anyone please tell me how does ranking work in jee advanced and how much rank do we need for iitd cse

Dear aspirant,

As you have not said anything about your category so i would be considering you as a general category student so to get IIT Delhi cse branch you need to be the best of best.

The cut off for the cse branch in the top 3-4 IITs generally stays under 110 so as per the previous years the cut off was 100 in iit Delhi.

Although various factors are considered while deciding the cut offs like number of candidates appearing in the examination, number of vacant seats in college, previous years cut offs and difficulty level of the paper.

For more information you can check out the link given below-

https://engineering.careers360.com/jee-advanced-college-predictor?utm_source=qna&utm_medium=jee_adv_cp

Dear student,

As you have not mentioned your Caste Category, I'm considering it as General Category and providing information based on it.

Previous year's cut-offs for Indian Institute of Technology, Delhi are listed below for B.E/ B.Tech Computer Science Engineering branch.

Opening Rank - 3

Closing Rank - 100

But cut-offs varies from year to year and depends on many factors like

• Seat Matrix
• Number of students appeared in the exam
• Difficulty level of the exam
• Caste Category of the candidates
• Previous year's cut-off trend

For Official cut-off go through below mentioned link.

https://josaa.nic.in/Counseling/seatallotmentresult/currentorcr.aspx

You can predict Colleges you can get using below mentioned College Predictor Tool.

https://engineering.careers360.com/jee-advanced-college-predictor?utm_source=qna&utm_medium=jee_adv_cp

To get more information about JEE Knockout go through below mentioned link.

https://learn.careers360.com/knockout-jee-main-april/

Hope this information was helpful to you.

Best of Luck!!