Hi I got 95.21 percentile in jee mains and 95.8% in 12th cbse.Can I get CSE in Thapar University,Patiala?
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Hi Khushboo,
Thapar University, Patiala gives admission by TWO modes-
- JEE Rank
- 12th Boards
According to your percentile, your rank in JEE Mains would be-
9,35,741 * 0.0479 = 44,822 (Approximately)
According to last year, the cutoff rank of CSE for Outside Punjab students was 46,770 (At Derabassi Campus).
For Punjab candidates, the cutoff rank was 2,23,247.
In 2017, the cutoff rank of CSE for Outside Punjab students was 42,872.
And, for Punjab candidates, it was 77,774.
Even if you don't get through mode 1, you will surely get it through mode 2.
Hope this helps you.
All the best!!!!
As you know, The Thapar Institute of Engineering and Technology University that is situated in Patiala, Punjab also offers International Engineering Program between Thapar University and Trinity College Dublin (TCD) for students admitted to B.E./B.Tech program at the university.
For this,
1-The candidate has passed 10+2 or equivalent examination with at least 60% marks (55% for SC/ST candidates) in aggregate of three subjects, namely, Physics, Mathematics and any one subject out of Chemistry, Biology, Biotechnology and Technical Vocational subject OR Minimum 60% (55% for SC/ST candidates) marks in a Diploma recognized by AICTE or a state board of technical education of at least 3-year duration.
2-The candidate has appeared in JEE (Main)-2019.
3-The candidate possesses a good moral character.
4-The candidate is a citizen of India.
5-The candidate has passed 10+2 examination in 2017, 2018,2019.
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