hi My Rank in JEE MAINS Is 68000 I am a general category student which NIT I Should apply please suggest ASAP
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Hello
Your profile suggests that your home state is Rajasthan
It's quite difficult to predict because cutoff keeps changing every year depending upon various factors like :-
******number of students that appeared in the jee main exam,
****** number of available seats,
****** performance of different students in the examination,
****** the category you belong etc.
With your 68k rank
You have low chance in any of NITs
For example,
Under other state quota , closing rank for some of the nits for which closing rank goes low are listed below along with their closing rank in the 6th round of josaa counselling 2020 for general category :-
-
National Institute of Technology Sikkim, Civil Engineering :- 47412
-
National Institute of Technology, Mizoram, Civil Engineering:- 49757
-
National Institute of Technology Agartala, Biotechnology and Biochemical Engineering :- 50,010
You can check the same at
https://josaa.nic.in/Result/Result/currentorcr.aspx
From above, it is clear that you need at least a rank of around 45,000 - 50,000 to get into an NIT .
But yes,
With your rank,
You have chances in GFTIs
For example,
In 6th round of josaa 2020, 68212 rank for general category got a seat in National Institute of Food Technology Entrepreneurship and Management, Sonepat, Haryana for Food Technology and Management which is a gfti
This prediction of colleges is based of past year data but cut off or closing rank changes every year depending upon many factors like the number of students that give the examination, difficulty level of the JEE main for different shifts etc so
To have a personalised report on your chances of getting a college you can go through our college predictor, it will give you complete list of colleges which you can get on the basis of the category you belong to, your home state, your gender etc, the link for jee main college predictor is provided below
https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer
Thank you
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