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How many 6-digit numbers are left if we subtract 50% of them?


Kamendra kumar 20th Mar, 2023
Answer (1)
Kamendra kumar 20th Mar, 2023

Total 6 digit numbers are 900000, On subtracting 50% of 900000, we get:

\begin{aligned}

&=900000\times(\frac{50}{100})\\

&=450000

\end{aligned}

Hence, a total of forty lakh, fifty thousand numbers are left when we subtract 50% of 900000

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