Question : How many job applicants had applied if the ratio of selected to rejected was 19 : 17? If 1200 less had been applied and 800 less were selected, then the ratio of selected to rejected would have been 1 : 1.
Option 1: 6000
Option 2: 7200
Option 3: 8400
Option 4: 4800
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Correct Answer: 7200
Solution :
Let there be 36x job applicants of whom 19x were selected, while 17x were rejected.
If (36x – 1200) had applied and (19x – 800) were selected, then
Rejected = (36x – 1200 – 19x + 800) = (17x – 400)
Given, Rejected : Selected = 1 : 1
⇒ (17x – 400) : (19x – 800) = 1 : 1
⇒ (17x – 400) = (19x – 800)
⇒ 19x – 17x = – 400 + 800
⇒ 2x = 400
$\therefore$ x = 200
So, the number of job applicants = 36x = 36 × 200 = 7200
Hence, the correct answer is 7200.
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