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How many litres of a 0.5 N solution of an oxidising agent are reduced by 2 litres of a 2.0 N solution of a reducing agent


Rk Raj 2nd Nov, 2018
Answer (1)
Vikas gehlot 3rd Nov, 2018

I think this is the simplest calculation for Redox reaction in Chemistry.

What do you need to do is just balancing.

From your knowledge of chemistry you know that

V1N1=V2N2

Therefore substituting the values we get the answer

2*2=0.5*V2

V2=4/0.5

V2=8

Therefore the answer to your problem is 8 litres

V2=8

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