Dear aspirant hope you are doing well. It's difficult to predict because cut keep changing every year depends on various factors.

1. No of seat available.

2. Difficulty level of exam.

3. No of student appear in exam.

Eligibility criteria for neet ug exam.

• :--->Minimum age of the candidates should be 17 years as of December 31, 2022
• :--->Candidate should passed the class 12th  exam from any recognised brard with physics, chemistry, biology (PCB) or (PCMB) with English is the compulsory subject.
• :--->Minimum aggregate marks: General category candidates must have passed the qualifying examination with 45% marks, while for SC/ST/OBC the minimum marks should be 40%
• :--->Reservation policy for pwd (handicap) : 3% of the reservation will be provided to the Person with Disability (PwD) candidates.

*Marks wise cut off for neet ug exam is  following*

• For General candidate-> 720-138

•  For OBC/SC/ST candidate  -> 137-108

•For  Gen PwD candidate  -> 137-122

•  For (OBC /SC / ST ) PwD candidates  -> 121-108

To get government medical college for veterinary course, a  candidate must score 500+ in neet ug exam to secure a seat, for obc category 450+ , for sc category 380+ , for St category candidate 320+ .

To get personalised report of  college, according to your neet ug score, rank, category, state. You can use neet ug college predictor link.

https://medicine.careers360.com/neet-college-predictor?utm_source=qna&utm_medium=neet_cp

Hope it's helpful for you thank you ......

Dear aspirant,

See like this it is a very difficult thing to.predict the marks because every year the dynamics changes as it further depends on certain factors like number of candidates appearing in the examination, number of vacant seats in college, previous years cut offs and difficulty level of the paper.

Regarding your marks on a general basis you would get around 400-500 for a veterinary government college.

For more information you can check out the link given below-

https://medicine.careers360.com/neet-college-predictor?icn=QnA&ici=qna_answer