Hello,

In 2019 the cut off was as follows for JNTU, Hyderabad for SC category

• EEE: 11617
• ECE: 8621

CBIT

• ECE: 10741
• EEE: 16778

Considering this you need to secure rank within 20,000. So to secure such rank you need to score 80-90 marks and you must have 550 or above marks out of 600 in Mathematics, Physics and Chemistry in first and second year. But cut off in 2020 changes depending on number of candidates appeared, difficulty of exam etc.

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