#IT
773 Views

how much load should be hung from the end of a steel wire of length 3.14 metre and of diameter 1 millimetre so that it increases in length by 1 millimetre why for steel is 2 into 10 to the power 11 SI unit


Aishree Dey 12th Jan, 2020
Answer (1)
KUNAL LANJEWAR 12th Jan, 2020

Hello,

We know that,

Young's Modulus = Stress / Strain

Stress = Force / Area = F / ( 0.25π x 1^2)

So, Stress = F / 0.785

Now, Strain = Change in Length / Original Length

So, Strain = 1 / 3140

So, Young's Modulus = ( F / 0/785 ) / ( 1 / 3140 )

We know that for steel, Young's Modulus = 2 x 10^5 N / mm^2

So, 2 x 10^5 = ( F / 0.785 ) / ( 1 / 3140 )

So, F = 50 N

Hence, 50 N load is required to hung from end of the steel wire to produce an elongation of 1mm

Best Wishes.

Related Questions

TAPMI MBA 2025 | Technology M...
Apply
MBA Admission Open in Technology Management and AI & Data Science | NAAC A++ | Institution of Eminence | Assured Scholarships
Amity University, Noida Law A...
Apply
700+ Campus placements at top national and global law firms, corporates, and judiciaries
Chitkara University MBA Admis...
Apply
NAAC A+ Accredited | 100% CAMPUS RECRUITMENT
Amrita Vishwa Vidyapeetham | ...
Apply
Recognized as Institute of Eminence by Govt. of India | NAAC ‘A++’ Grade | Upto 75% Scholarships | Extended Application Deadline: 30th Jan
Great Lakes PGPM & PGDM 2025
Apply
Admissions Open | Globally Recognized by AACSB (US) & AMBA (UK) | 17.3 LPA Avg. CTC for PGPM 2024 | Extended Application Deadline: 10th Feb 2024
Amity University Noida B.Tech...
Apply
Among Top 30 National Universities for Engineering (NIRF 2024) | 30+ Specializations
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books