How much minimum rank required for ii it's any
Hello there,
To get a seat in IIT one has to first clear JEE Mains as per his/her category only then he/she is eligible to sit in JEE Advanced. The admission in IITs will be done through JEE Advance. One has to secure the minimum aggregate marks/percentile as per their category in JEE Advance to get their names on the rank list. Similarly, the cutoffs vary from one IIT to another and also varies from branch to branch. Below I have provided 2019 JEE Mains cutoff category wise & previous year JEE Advanced qualifying cutoff -
2019 JEE Mains Cutoff (percentile) :
- CRL : 89.75
- GEN-EWS : 78.21
- OBC-NCL : 74.31
- SC : 54.01
- ST : 44.33
- PwD : 0.11
2018 JEE Advance qualifying marks :
- CRL : 90
- OBC-NCL : 81
- SC : 45
- ST : 45
- CRL PwD : 45
- OBC-NCL PwD : 45
- SC PwD : 45
- ST PwD : 45
- Preparatory course rank list : 23
I have also provided the minimum percentage of aggregrate marks category wise required to get ones name in the rank list :
- CRL : 35
- GEN-EWS : 31.5
- OBC-NCL : 31.5
- SC : 17.5
- ST : 17.5
- CRL PwD : 17.5
- OBC-NCL PwD : 17.5
- SC PwD : 17.5
- ST PwD : 17.5
- Preparatory course rank list : 8.75
You can also go through this link and checkout the detailed previous years cutoff for JEE Advanced : https://engineering.careers360.com/articles/jee-advanced-cutoff
Also , you can visit this link and checkout the cutoffs branch and category wise for all the IITs : https://engineering.careers360.com/articles/jee-advanced-cutoff-for-iits
Hope this helps you . Good Luck !!!
