how much rank is needed in JEE advanced to get into IIT Kharagpur ,Kanpur, Roorkee ,Goa ,Hyderabad with mechanical engineering and aerospace engineering dual degrees ....
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The closing ranks for various courses varies every year.According to JEE Advanced 2019 the closing ranks for Mechanical Engg for various categories are given below :
IIT Kharagpur :
General - 2259
OBC - 921
EWS - 178
SC - 453
ST - 268
IIT Kanpur :
General - 2108
OBC - 890
EWS - 181
SC - 576
ST - 342
IIT Roorkee :
General - 2748
OBC - 1084
EWS - 231
SC - 654
ST - 329
IIT Hyderabad :
General - 3609
OBC - 1260
EWS - 298
SC - 840
ST - 390
IIT Goa :
General - 9473
OBC - 3605
EWS - 1052
SC - 1583
ST - 710
The closing ranks for Aerospace Engg for various catogories are given below :
IIT Kharagpur :
General - 3822
OBC - 1651
EWS - 398
SC - 1079
ST - 590
IIT Kanpur :
General - 3497
OBC - 1717
EWS - 357
SC - 1084
ST - 608
Visit the links below for more details regarding the closing ranks :
https://engineering.careers360.com/articles/iits-cutoff-for-b-tech-mechanical-engineering
https://engineering.careers360.com/articles/iits-cutoff-for-b-tech-aerospace-engineering
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