how much rank required to get NIt warangal in coputer science for obc male
Hi
This is a bit difficult to predict the rank required in JEE mains to get a seat as cut off keeps changing every year depending upon various factors like number of students that appeared in the exam, kind of marks obtained by them , toughness level of the jee main examination , number of seats available for the branch you want etc.
But yes,
When we go through previous year trend then ,
In round 6 of josaa counselling 2020 , the closing rank for gender neutral for obc category for computer science for NIT Warangal is provided below :-
Under home state
-
Computer science :- 826 obc rank
For other state
-
Computer science :- 594 obc rank
You can check the same at
https://josaa.nic.in/Result/Result/currentorcr.aspx
Thus, to get into NIT Warangal for computer science if you have home state quota then you must target OBC rank of around 800 while for other state target rank of around 500 to be on the safer side
To predict your rank, you can use
To have a personalised report on your chances of getting a college you can go through our college predictor, it will give you complete list of colleges which you can get on the basis of the category you belong to, your home state, your gender etc, the link for jee main college predictor is provided below
https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer
If you have any other doubt then you can always reach us to clear them :) we are always available to help you out and guide you
Thankyou
Hello STudent,
Actually it is quite impossible to tell about how much rank you should get to get admission in National Institute of Technology Warangal in computer science. The cutoff trend changes every year and it depends upon some factors. According to previous year data , for all India quota 589 of OBC male gate chance in CSE, and for home state quota it is 792.
Click on the link below to predict your college
https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer
