how to calculate tnea engineering cutoff 2021 for tn students
Recommended : Get important details about JNEC Aurangabad.
Download Brochure
Answer (1)
19th Jul, 2021
Hello David!!
Engineering cutoff for Tamil Nadu Engineering Admissions is calculated based upon the formula as follows,
Cutoff = M + (P/2) + ( C/2)
where, M stands for maths mark, P stands for Physics mark and C stands for Chemistry mark.
For example,
Maths mark = 95, Physics mark = 93, Chemistry mark= 97, then the cutoff is
Cutoff = 95 + (93/2) + (97/2)
= 95 + 46.5 + 48.5 = 190
So the cutoff is 190 out off 200.
Hope this helps you.
Best of luck!!
Comments (0)
