161 Views

how to find the point of intersection of the lines 5x-6y-1=0 and 3x+2y+5=0.


kallamvgreddy123 16th Mar, 2020
Answer (1)
KUNAL LANJEWAR 16th Mar, 2020

Hello,

The two given lines are

5x - 6y = 1 ...(i) and

3x + 2y + 5 = 0, i.e.,  3x + 2y = - 5 ...(ii)

Now, (i) × 3 and (ii) × 5, we get,

15x - 18y = 3 and

15x + 10y = - 25

On subtracting ( i ) and ( ii ), we get

- 18y - 10y = 3 + 25

So, - 28y = 28

Hence,  y = - 1

Now, putting y = - 1 in (i), we get

5x - 6 (- 1) = 1

So, 5x + 6 = 1

So, 5x = 1 - 6

Hence,  x = - 1

So, the point of intersection of the lines (i) and (ii) is (- 1, - 1)

Best Wishes.

1 Comment
Comments (1)
16th Mar, 2020
thankyou
Reply

Related Questions

UPES Integrated LLB Admission...
Apply
Ranked #28 amongst Institutions in India by NIRF | Ranked #1 in India for Academic Reputation by QS University Rankings | 16.6 LPA Highest CTC
SLAT 2025 - The Symbiosis Law...
Apply
Conducted by Symbiosis International (Deemed University) | Ranked #5 in Law by NIRF | Ranked #2 among best Pvt Universities by QS World Rankings
Jindal Global Law School Admi...
Apply
Ranked #1 Law School in India & South Asia by QS- World University Rankings | Merit cum means scholarships
Symbiosis Law School Pune Adm...
Apply
NAAC A++ Accredited | Ranked #5 by NIRF
Nirma University Law Admissio...
Apply
Grade 'A+' accredited by NAAC
ISBR Business School PGDM Adm...
Apply
Ranked as Platinum Institute by AICTE for 5 years in a row | Awarded Best Business School of the Year
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books