how to find the point of intersection of the lines 5x-6y-1=0 and 3x+2y+5=0.
Answer (1)
16th Mar, 2020
Hello,
The two given lines are
5x - 6y = 1 ...(i) and
3x + 2y + 5 = 0, i.e., 3x + 2y = - 5 ...(ii)
Now, (i) × 3 and (ii) × 5, we get,
15x - 18y = 3 and
15x + 10y = - 25
On subtracting ( i ) and ( ii ), we get
- 18y - 10y = 3 + 25
So, - 28y = 28
Hence, y = - 1
Now, putting y = - 1 in (i), we get
5x - 6 (- 1) = 1
So, 5x + 6 = 1
So, 5x = 1 - 6
Hence, x = - 1
So, the point of intersection of the lines (i) and (ii) is (- 1, - 1)
Best Wishes.
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