how to take out mod of cos theta = A vector . B vector upon A B if A vector = 3 i cap + 4 j cap and B vector = 12 i cap + 5 j cap . explain in detail how to take out mod
Answer (1)
Student Expert
10th Sep, 2020
Hey
I suppose it will be like
A vector into B vector is (3*12)+(4*5)=36+20= 56
AB= root under (3 square+4 square) * root under (12 sqaure + 5 square)= 5+13=18
Hence mod of cos theta will be : 56/18= 3.11(which is not possible hence I guess you got the question wrong and it should have been either -4j cap or -5 j cap(one of these)).
Comments (0)
