156 Views

how to take out mod of cos theta = A vector . B vector upon A B if A vector = 3 i cap + 4 j cap and B vector = 12 i cap + 5 j cap . explain in detail how to take out mod


jaywadmare 10th Sep, 2020
Answer (1)
ojaswiyolo Student Expert 10th Sep, 2020

Hey

I suppose it will be like

A vector into B vector is (3*12)+(4*5)=36+20= 56

AB= root under (3 square+4 square) * root under (12 sqaure + 5 square)= 5+13=18

Hence mod of cos theta will be : 56/18= 3.11(which is not possible hence I guess you got the question wrong and it should have been either -4j cap or -5 j cap(one of these)).

Related Questions

Amity University | B.Sc Admis...
Apply
Ranked amongst top 3% universities globally (QS Rankings)
Woxsen University B.Sc. Admis...
Apply
Build Your Own Degree - Choose any 3 out of 8 Electives | 100% Plcament track | 100+ Global Partners | 200+ Industry Interactions
Symbiosis School for Liberal ...
Apply
Admissions open for BA/BSc. Liberal Arts (Honours) & BA / BSc. Liberal Arts (Honors) with Research
UPES B.Sc Admissions 2025
Apply
Ranked #46 amongst Universities in India by NIRF | Ranked #1 in Academic Reputation in India by QS World University Rankings
KL University B.Sc Admissions...
Apply
A++ Grade by NAAC | Recognized as Category-1 University by UGC | 100% Placement, 60 LPA Highest CTC, 400+ Recruiters
Alliance University B.Sc. Adm...
Apply
Highest CTC 60.1 LPA | 800+ Recruitment Partners
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books