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Hello Aspirant,
The exact prediction would be difficult about the exact rank & admission possibilities. You may calculate your expected rank by this formula
100 - your total percentile score is the percentage of people ahead of you. 874469 are the number of candidates appeared for Jan exam. So rank formula is (100 - your total score) X 869010 /100. If the number of candidates for April exam increased to 1200000 then your final rank shall be (100 - your total score) X 1200000/100
Using the formula
(100 - your total score) X 869010 /100
Your probable rank will be 17,380.
As per the previous year cutoff, You can get
B.Tech/B.Arch Admissions OPEN
National Institute of Technology Karnataka Surathkal, National Institute of Technology Warangal, Motilal Nehru National Institute of Technology Allahabad Prayagraj, National Institute of Technology Rourkela, Malaviya National Institute of Technology Jaipur- Civil & Chemical Engineering.
To know your other admission possibilities & branches, You can use JEE Main College Predictor tool.
JEE Main College Predictor – Know your College Admission Chances Based ...
Good Luck!
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