i am from obc category i have got 93.44 percentile in jee 2020 i want to take electronic branch how is my marks and where can i get
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Answer (1)
Student Expert
22nd Jan, 2020
Hello,
Your expected rank can be calculated using the formula given below
(100-total percentile)*869010/100
In your case it is
(100-93.44)*869010/100=57007
And your category rank will be around 25k-30k.
So it is not possible to get seat in NITs.However if you hold a domicile of a particular state which has NITs you have chances of getting a seat with this rank as the cut off for home state candidates and other state candidates is different.So if you tell us your state we may help you further.
You can predict the colleges which you may get using the link below
Your expected rank can be calculated using the formula given below
(100-total percentile)*869010/100
In your case it is
(100-93.44)*869010/100=57007
And your category rank will be around 25k-30k.
So it is not possible to get seat in NITs.However if you hold a domicile of a particular state which has NITs you have chances of getting a seat with this rank as the cut off for home state candidates and other state candidates is different.So if you tell us your state we may help you further.
You can predict the colleges which you may get using the link below
2 Comments
Comments (2)
I m from bihar
Reply
Pratibha Jayswal
A candidate belonging to Bihar secured a seat in NIT, Patna in electronics and communication engineering with rank 31200 in 2019 in open category and a candidate belonging to Bihar secured a seat in the same with a rank 10917 belonging to OBC-NCL.Considering this you may not get seat in NIT, Patna too as your category rank will be around 25k and it is difficult to get seat in other NITs too.However, you have good chance to qualify JEE main and appear for JEE advanced.So it is better to prepare for JEE advanced and do well.
And the cut off is subjected to change it may increase or decrease slightly.
And the cut off is subjected to change it may increase or decrease slightly.
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