I am getting 121 marks in 8th January second shift of jee mains 2020 what can be my percentile.
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Hello Vaibhav! As you must be knowing that now jee mains is conducted twice a year, so basically you will get your correct rank after the aprilattempt. The paper in which you scored the highest will be considered for your rank.
Now lets try to calculate your percentile which is calculated according to the shift in which you gave your paper. Your percentile would be :
(No. of people having less than 121 marks in second shift/total number of students present in second shift)*100
According to last year's data your percentile will fall between 97.13841571 - 96.41990133. This percentile will vary due to many factors like no. of students in your shift or the level of the paper.
You can calculate your rank according to formula:
1+((100-P) * No. of total students appearing)/100)
Considering last year's data your rank will fall between 18378 - 57131.
For further information on your rank, refer to our jee mains rank predictor:
You can check our jee mains pack to score even more higher in your april attempt: https://learn.careers360.com/knockout-jee-main-april/
Hope it helps. All the best!
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