I am getting 127 marks in jee advanced 2020 according to official answer key. What rank can I expect ?

Hello There ,

Congratulations on a good score , according to last year your rank would be around 7000-10000 , in general category .This can however vary as rank varies depending on toughness of exam . With this rank you can get many good iit's like BHU ,Ropar , Dhanbad , Tirupati etc in some decent core branches like mechanical , chemical , electrical , civil etc . You can also get , IIST , IISER , RGIPT and IIPE also with your rank .

For more details you can refer the following page. -

https://engineering.careers360.com/articles/jee-advanced-cutoff-for-iits

https://engineering.careers360.com/articles/jee-advanced-cutoff

Hope it Helps  .

Use careers360 JEE Advanced college predictor to predict colleges like iit , iipe , iiser , iist etc .

https://engineering.careers360.com/jee-advanced-college-predictor?icn=QnA&ici=qna_answer

Hey,

Honestly speaking that for a certain marks your obtained rank vary each year depending upon the several important factors like number of appeared canditates, number of successful candidates, total number of available seats, previous year's cut-off trend etc, so it's not so easy to estimate your accurate rank in any particular year for this type of examination like JEE Advanced 2020.

Still as per our experience, I can assure you that with this marks your rank would be in between 28205-30115 . You can use the following website to ensure my assumption:

https://engineering.careers360.com/articles/jee-advanced-rank-predictor

However you've not mentioned your category in your question, so it's quite difficult for us to make any accurate comment regarding your admission possibilities. Still it can be assumed that if you're a General-UR or OBC category candidate, then it's quite difficult for you to grab a seat in any top and renowned IIT instituions in India. For more information please use our College predictor tool:

https://engineering.careers360.com/jee-advanced-college-predictor?icn=QnA&ici=qna_answer

Wish you all the best.