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I am Moin khan,I got 92.1467 percentile in jee main 2019 which is held on 12th jan'19,Can i get any good NIT or IITG. Also i want know rank


Moin Khan 11th Dec, 2018
Answer (1)
Vikas gehlot 20th Jan, 2019

Hello

Greetings

Your percentile is 92.1467 It means 92.1467% student of the Total student appeared for the Exam are Behind You Therefore 7.8533% students of the Total students appeared for the exam are Ahead of You, Therefore Your calculated rank is 68674.7

Your Rank would change Either Your Percentile Score is Increases in the next attempt or Number of Student increases in the Next attemptIf the Number of Student Increases to 1400000 and Your percentile remain same then Your New rank would be 109946

As per Your current Performance You may be eligible for JEE Advance But the final cutoff will be released once the JEE Main April gets Over

B.Tech/B.Arch Admissions OPEN

Apply to Amrita University B.Tech 2025

If Your Percentile Score Increases in the Next attempt Then Your Rank would Be calculated By the Following Formula

(100 - your total percentile score (Higher of two)) X Student appeared in JEE Main/100

You can Use the college Predictor to know about  the possible colleges in which You may get admission by Just following the link given below


https://engineering.careers360.com/jee-main-college-predictor

At this rank It is Not possible to get admission into any NIT, Please try better in the next attempt of JEE Main

You should Try to get more than 98 percentile for NIT

Hope this Helps All the Best

1 Comment
Comments (1)
20th Jan, 2019
For result predictor in carrer 360 .It is asking total marks obtained  in jee main what should be inputed in  blank pls suggest me
Reply
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