Hello,


Sastra Deemed University will offer admission in 2019 under the following two streams:

Through stream 1:
Admissions to 70% of the seats will be made through stream 1 on the basis of JEE Main scores and normalized scores of the 10+2 or equivalent exam.
The 25% weightage will be given to JEE Main scores and the remaining 75% will be given to marks scored in 10+2 or equivalent examination.
The combined scores will be used to prepare the rank list and candidates will be invited for admission on the basis of the rank list.

Through stream 2:   The remaining 30% of the seats will be filled through stream 2
Only 10+2 (or equivalent) normalized scores will be considered while preparing the rank list of stream 2.
Candidates can apply through both the streams. In case, a candidate has not appeared for JEE Main 2019 exam and has applied for stream 1, the weighted score for the 25% will be considered 0 but the qualifying exam aggregate scores will be given 75% weightage to arrive at the combined score. However, in case of stream 2, the qualifying exam scores will be given 100% weightage.


https://engineering.careers360.com/articles/sastra-university-btech-eligibility-criteria


I hope this helps.

SASTRA University Thanjavur

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