i got 109 marks in jee advanced sc category female can i get cse in iit Bombay and what will be my rank? which more IIT i can get? please sir/ ma'am reply all my this questions! thank you
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Hi Anjali.
Congratulations for scoring 109 marks in JEE Advanced . With such a score, your CRL Rank is nearly 18,000 . With such a rank, category and gender, unfortunately , you won't be able to get CSE at IIT Bombay , or in fact, CSE in any IIT . However, you may look out for these branches at the following IITs :
- MECHANICAL ENGG.
- IIT Bhubaneshwar
- IIT Bhilai
- CIVIL ENGG.
- IIT Bhubaneshwar
- CHEMICAL ENGG.
- IIT Patna
- IIT Jammu
- IIT Dhanbad
- MINING ENGG.
- IIT Kharagpur
- IIT Varanasi
- BIOTECHNOLOGY
- IIT Varanasi
- CHEMISTRY
- IIT Kharagpur
USE THIS JEE Advanced College Predictor for more info:
For expert guidance from Careers360 , refer here, https://www.careers360.com/btech-companion/order-summary?icn=companion_order_summary&ici=companion_btech_dashboard
- Hope this helps. Thanks .
[Note: These are predictions from previous years' data. This year's cutoffs have not been released yet.]
[Cutoffs and ranks depend on various factors like:
- Number of Candidates.
- Performance in exam.
- Difficulty of exam.]
Hello there!
First of all congratulations on qualifying JEE advanced and as you have mentioned your score 109. if we see previous year marks vs rank, your rank and 13 K to 15k. also please note that this is just a predicted rank which is based on previous years rank fashion. you cannot get IIT Bombay for studying BTech computer science at this rank but there are other IITs you can get admission to. Some of them are:
- IIT KHARAGPUR (B.TECH IN MINING / B.sc physics)
- IIT VARANASI (B.TECH IN CHEMICAL engg. )
- IIT BHUBANESHWAR ( B.TECH+M.TECH IN MECHANICAL ENGG.)
- ISM DHANBAD (B.TECH IN ENGG. PHYSICS)
- ISM DHANBAD ( B.TECH IN MECHANIC ENGG.)
PLEASE NOTE THESE COLLEGES ARE PREDICTED BASED ON LAST YEAR CLOSING RANKS FOR DIFFERENT BRANCHES.
PREDICT YOUR COLLEGE FROM THIS JEE ADVANCED COLLEGE PREDICTOR TOOL:
hope this helps.
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