I got 125 marks on 27th August 2nd attempt and i belong to OBC category, What will be my percentile?Can i get Admission in NITs? ( HOME STATE: TELANGANA).

Hi

With 125 marks

• Your percentile  will be around 95.59 - 97.37 considering moderate level paper and if we go with 95.59 percentile then your rank will be around  45114 - 50715 as per our rank predictor at

  

  JEE Main Rank Predictor 2021 - Predict your JEE Main 2021 Rank, JEE Main Percentile Calculator

  JEE Main Rank Predictor - Know your expected IIT JEE Main 2021 Rank by using Careers360 JEE Main rank predictor tool based on JEE Mains scor ...

Your obc rank will be around 14k

With your rank , you have chances in following NITs which are listed below along with their closing rank in 6th round of josaa counselling 2020 under other state -

-----------) NIT Mizoram ,civil engineering :-14730 obc rank

-----------) National Institute of Technology, Jalandhar,  biotechnology engineering :-14504 obc rank

-----------) Nit nagaland ,Electronics and Instrumentation Engineering (4 Years, Bachelor of Technology) :-  15340 obc rank

-----------) National Institute of Technology AgartalaProduction Engineering (4 Years, Bachelor of Technology :- 15659  obc rank

And a few more

You can check the closing ranks  at official website of josaa by going through the link given below

https://josaa.nic.in/Result/Result/currentorcr.aspx

Above prediction has been made  considering  past year cut off data but  closing rank for colleges varies every year depending upon many factors like jee main question paper difficulty, number of students writing the exam etc so

To have a personalised report on your chances of getting a college you can go through our college predictor, it will give you complete list of colleges which you can get on the basis of the category you belong to,  your home state, your gender etc, the link for  jee main college predictor is provided below

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

To help you further,

To give you an idea of qualifying cut off, JEE mains 2020  qualifying  CUT OFF percentile to be eligible for jee advanced is given below for different category

>>>> General :-     90.3765335

>>>> GEN-EWS :-  70.2435518

>>>> OBC-NCL :-  72.8887969

>>>> SC     :-           50.1760245

>>>> ST :-                39.0696101

>>>> PwD :-            0.0618524

You can check the same at our page the link is provided below

https://engineering.careers360.com/articles/jee-main-cutoff

Thankyou