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i got 70 marks in july 25th second shift (st cateogry) what will be my percentile, CRL rank and category rank and please let me know which NIT can i get and with specific branches.Thankyou.


vivek ramavath 30th Jul, 2021
Answer (1)
Anurag Khanna 30th Jul, 2021

Hello Aspirant,

According to the percentile you have mentioned your percentile, CRL rank and ST rank are expected to be in the range of 85.96 - 89.08 , 127875 - 143750 and 6000-8000 respectively, you can check out marks Vs CRL ranks Vs Percentile from the link given below :-

https://engineering.careers360.com/articles/jee-main-marks-vs-percentile

Or

You can also use JEE-Main Rank Predictor to predict your rank :-

So on such rank and category you have SOME chances to get the enlisted NITs if you deserves Home state quota :-

  • National Institute of Technology Durgapur - Electrical Engineering (6908)
  • National Institute of Technology Agartala - Computer Science and Engineering (16140)

If don't deserves Home state quota then :-

  • Indian Institute of Information Technology Manipur - Electronics and Communication Engineering (6065)

You can check out previous year's cut-offs from the official website of JOSAA as given below :-

https://josaa.nic.in/Result/Result/currentorcr.aspx

Note that the above prediction is made on the basis of latest cut-offs available on official website of JOSAA or CSAB and the cut-offs are bound to change every year depending upon various factors such as the number of candidates appearing in an examination, the number of candidates qualifying an examination, difficulty level of the paper, and so on.

So you can use JEE-Main College Predictor to predict your chances of admission in different engineering colleges of India on the basis of your JEE-Main 2021 result :-

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

You can also check out the JEE-Main 2021 qualifying cut-off (expected) for JEE-Advance 2021 from the link given below :-

https://engineering.careers360.com/articles/jee-main-cutoff

I hope this information helps you.

Good Luck!!

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