I got 71 percentile in jee mains January first shift in OBC catagory.what will rank
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Hello Aspirant,
It would be difficult to tell you the exact rank. You may calculate your expected general rank by this formula
100 - your total percentile score is the percentage of people ahead of you. 874469 are the number of candidates appeared for Jan exam. So rank formula is (100 - your total score) X 869010 /100. If the number of candidates for April exam increased to 1200000 then your final rank shall be (100 - your total score) X 1200000/100
Using the formula
(100 - your total score) X 869010 /100
your Probable general rank will be 2,52,012.
Based on this percentile the chances seems less to get a seat in NITs, IIITs & GFTIs.
You can try for the state level counselling. I would also suggest you to appear for JEE Main April Session 2020 which application form is expected to start from 7th February, 2020.
To know your admission possibilities in state level counselling you can use JEE Main college predictor tool given below.
https://engineering.
Good Luck!
https://engineering.careers360.com/articles/jee-main-rank-predictor
In the following link you will find the expected cutoff for the 2020 for all NITs, IITs etc and you'll also find the previous year cutoffs
https://engineering.careers360.com/articles/jee-main-cutoff
Hello!!
To calculate your JEE main rank,you can use this formula ((100-your total percentile)*869010/100).This formula will give your general category rank.And for your percentile,your rank calculated is approximately 252012.Your rank is greater than the closing rank of many institutes.So try to appear for appear for JEE main April exam if you are desperate to get an admission into NITs or IITs.
To know about all the possibilities of your admission into various colleges other than NITs and IIITs,visit the below given website.You will have to enter the details asked such as your percentile,category,home state etc..and the possibilities will be predicted.
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