I got 77.35 percentile in JEE main 2019, I am SC from kerala Will I get CS NIT Calicut. Wht would be my category wise Ranking?

Hello. You have a decent score. It means that almost 22.65% of the total no. of students who appeared in the exam are ahead of you. (Tot. students- 874469)

It is difficult to tell if you will be getting nit college now since your percentile and rank may differ because it depends on the tot. no. of students appearing in the April exam. NTA will release the Overall merit list based on the no. of students appeared and best of two attempts of the students appearing twice. So to know your exact rank and a particular college cutoff you need to wait until the April exam ends.

But for now you can check your rank from the below formula.

Rank - (100-percentile score)*(874469/100)

According to this your approx rank is 198067.

But this is oviously not your final rank as it will be different if the total no. of students appearing in the April exam changes (most oviously no. of students appearing in April will be higher).

Since this percentile and two attempts system is adopted from this year only so I cannot comment on the exact cutoff for different qoutas. But in general from the previous cutoffs I can tell you that any rank below 2,00,000 will get you qualified to sit for JEE Advanced.

I would recommend you to appear for the 2nd attempt and try to score 80+ percentile to get a good college.

For more details you can check the below link.

Https://www.entrance360.com/engineering/how-to-calculate-rank-for-jee-mains-2019/

Hope this helps. For any query you can comment down below.