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i got 78.37 percentile in jee mains general category. can i get sardar patel Institute of technology, mumbai or kj somaiya, mumbai


This and That 19th Dec, 2019
Answers (3)
pdwords Student Expert 28th Jan, 2020

Hello,


Your rank can be calculated by this formula: 100 - your total percentile)*869010/100. Your estimated rank would be  1,87,966.


According to 2019 cut-offs for General Category at Sardar Patel Institue of Technology for different departments based on JEE Mains has been as follows-


  • Computer Engineering-6466
  • Electronics Engineering - 28131
  • Electronics and Telecommunication Engineering - 17468



And, for KJ Somaiya College of Engineering, Mumbai, cut offs for different department for General based on JEE Mains has been as follows-


  • Computer Engineering-12233
  • Electronics Engineering - 47065
  • Electronics and Telecommunication Engineering - 30083


With such a high cut-offs in the last year, it's highly difficult to secure a seat in any of the two college.


Subhodeep Biswas 28th Jan, 2020
Hey there hope you're doing well.
Dear aspirant, according to your percentile score in JEE MAIN your expected rank is about 1,86,966.
The cutoffs for both the colleges Sardar Patel Institute of Technology as well as KJ Somaiya,Mumbai are very high .
Let me give you a glimpse of that.
The previous year cutoffs for branches on JEE AIR's were.
Branch______ JEE AIR closing rank______ state rank
_______________KJ SOM_____ SPIT
1.CSE________ 12,233_____6,466____159 ____173
2. E & Tele____ 30,053____17,468 __139 ____161
3.EE __________47,065 ____28,131 __132 ____104
4.IT___________ 16,558 ____9,917____151____170
5.ME __________22,030 _ _______________146 _
The above data were for kj somaiya and SPIT Mumbai.
Thank you hope this helps you!
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Sharon Rose Student Expert 28th Jan, 2020
Hello,
Considering your percentile your expected rank will be around 187966.You can calculate your expected rank using the formula given below
(100-your total percentile)*869010/100
869010 is the total number of candidates appeared in JEE main January session.
So it is (100-78.37)*869010/100=187966
It is expected that 1200000 candidates will appear in April session so the formula is given as (100-your total percentile)*1200000/100.

Now, the cut off for 2019 for SPIT, Mumbai is given below branch wise
  • Computer science engineering- 118
  • Information technology- 252
  • Electronics and telecom Engineering- 561
  • Electronics Engineering- 834

The cut off for KJ SOMMAIYA College of Engineering, Mumbai is given below branch wise
  • Computer science engineering- 341
  • Information technology - 741
  • Mechanical Engineering - 999
  • Electronics and Telecom Engineering- 1652
  • Electronics Engineering- 2058

Considering 2019 cut off trends you may not get seat in either of the colleges.It is better if you prepare for JEE main April session as you may not qualify JEE main in January session.

You can predict the colleges in which you may get using our JEE main college predictor

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