I got 82.5 percentile in Jee mains(OBC) Can I get Admission in BCE bhagalpur or MIT muzaffarpur ?
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Answer (1)
Student Expert
22nd Jan, 2020
Hello,
Your expected rank will be 152076.You can calculate your expected rank using the formula given below
(100-your total percentile)*869010/100
In your case it is
(100-82.5)*869010/100=152076
And your expected rank will be around 60k-70k.With this rank it is difficult to get seat in this college considering 2019 cut off.
The cut off is as follows in 2019 for each branch for OBC category
Your expected rank will be 152076.You can calculate your expected rank using the formula given below
(100-your total percentile)*869010/100
In your case it is
(100-82.5)*869010/100=152076
And your expected rank will be around 60k-70k.With this rank it is difficult to get seat in this college considering 2019 cut off.
The cut off is as follows in 2019 for each branch for OBC category
- Computer science engineering 240-334
- civil engineering 297-319
- electrical engineering 519-561
- Mechanical engineering 600-688
- electronics and electrical engineering 640-756
1 like
2 Comments
Comments (2)
thanks
Reply
Ankur
And the cut off for MIT, Muzaffarpur was as follows for OBC for 2019
Civil engineering 326-363
Information technology 421-555
Electrical engineering 449-477
Electronics and electrical engineering 575-735
So you may not get in MIT, Muzaffarpur.
Civil engineering 326-363
Information technology 421-555
Electrical engineering 449-477
Electronics and electrical engineering 575-735
So you may not get in MIT, Muzaffarpur.
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