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I got 82.5 percentile in Jee mains(OBC) Can I get Admission in BCE bhagalpur or MIT muzaffarpur ?


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Ankur 13th Dec, 2019
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Sharon Rose Student Expert 22nd Jan, 2020
Hello,
Your expected rank will be 152076.You can calculate your expected rank using the formula given below
(100-your total percentile)*869010/100
In your case it is
(100-82.5)*869010/100=152076
And your expected rank will be around 60k-70k.With this rank it is difficult to get seat in this college considering 2019 cut off.
The cut off is as follows in 2019 for each branch for OBC category
  • Computer science engineering 240-334
  • civil engineering 297-319
  • electrical engineering 519-561
  • Mechanical engineering 600-688
  • electronics and electrical engineering 640-756
So it is better if you better if you prepare for JEE main April session.

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22nd Jan, 2020
thanks
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Student Expert 22nd Jan, 2020
Ankur And the cut off for MIT, Muzaffarpur was as follows for OBC for 2019
Civil engineering 326-363
Information technology 421-555
Electrical engineering 449-477
Electronics and electrical engineering 575-735
So you may not get in MIT, Muzaffarpur.
Reply
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