Hello student,

Congratulations for scoring such impressive percentile in MHTCET 2021. With this good percentile, you can easily get admission in some of the decent colleges in the state for CS/IT branches. Also, as you are an OBC category student, your chances of getting a good and better college increases.

Here is a list of some of those colleges:

• Atharva College of Engineering
• Shah and Anchor College of Engineering
• DY Patil College of Engineering
• AISSMS
• JSPM Rajarshi Shahu College of Engineering
• Rajiv Gandhi Institute of Technology

Click here to get the prediction of colleges available to you

Click here to check out the previous year cut offs

I hope this helps, All the Best!

Hello Aspirant,

On such percentile and category you have good chances of getting some colleges with CSE branch through MHT-CET counselling according to previous year's cut-off.

As we go through previous year's cut-off then it shows that you can get following colleges :-

Department of Technology, Shivaji University

ICEM - Indira College of Engineering and Management

Pune District Education Association's College of Engineering

Nutan Maharashtra Institute of Engineering and Technology

JSPM - TSSM's Padmabhooshan Vasantdada Patil Institute of Technology

Marathwada Mitra Mandal's Institute of Technology

And some more. You can check out previous year's cut-offs from the link given below :-

https://engineering.careers360.com/articles/mht-cet-cutoff

Note that the above prediction is made on the basis of previous year's cut-off and the cut-offs are bound to change every year depending upon various factors such as the number of candidates appearing in an examination, the number of candidates qualifying an examination, difficulty level of the paper, and so on.

To have a list of all those colleges which you can get based upon your percentile and category you can use MHT CET College Predictor because it will make you comfortable while choice filling in counselling :-

https://www.careers360.com/mht-cet-college-predictor?icn=QnA&ici=qna_answer

I hope this information helps you.

Good Luck!!