Answer (1)
Soumili Majumdar 23rd May, 2020
Hello there,
According to the rank formula, [100-83.5*869010/100], your All India Rank is 143386 approximately, where 83.5 is your percentile and 869010 is the total no.of candidates who appeared for JEE Main Jan session. Analysing the previous year data, the cut-off rank of JIIT, Noida are :

For JIIT sector 62,
CSE- 65k approx.
ECE - 90k approx.

For JIIT sector 128,
CSE - 105000 approx.
ECE - 150000 approx.

Since you have not mentioned your category, I'm assuming that you are from the general category. So there's a chance that you can get admission in JIIT sector 128.

Hope this answer helps you.
Good luck!!
1 Comment
Comments (1)
23rd May, 2020
thank you
Reply
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