I got 84.31 percentile in Jee mains am belong to obc category.can I get an NIT
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Dear student,
As per your percentile, your probable General rank is 1,37,204. It is difficult to calculate your category specific rank as the cutoffs vary according to the Examining Authorities discretion. However, based on this, I think securing a seat in NIT will be difficult as the cutoff is usually very high. But for your reference, please read through the following link very carefully-
https://engineering.careers360.com/articles/jee-main-cutoff
This will help you with the detailed past years' NIT cutoffs. All the very best!
To get admission in any of the NITs, the minimum required percentile is 98+%ile.
Based on your percentile, there are nearly no chances to get any NITs. So if you have a target of NIT, then you should give yourself one more chance by appearing in the second attempt of JEE Mains-April. Work hard + smart and prepare well.
Well, according to expert team, the candidates having 85+%ile will qualify for JEE Advanced. This is just the predicted range and it may vary. Whereas, the final cutoff percentile along with the ranks will be released by NTA after the April session of JEE Mains exam.
Hope this helps.!
Good Luck.!
For any further information-queries, you can ask here at CAREERS360 anytime.!
hii nagaraj
i am sorry to say you need atleast have 95+ percnetile to get the NIT while kindly hope if you get since you have the rank to be yet released but chances are quite low
You need to find rank first to get to know more infomoration
The official Jee rankings will be released after the examination in April. You cod use the formula to predict your rank:
JEE Main 2019 rank (probable) = (100- NTA percentile score ) X 874469 /100
However,this rank may change as only the best of the two scores will be considered for the final rank list.
Please refer the below link
Https://engineering.careers360.com/percentile-predictor-result/1094?s=39600026441548134962
Https://engineering.careers360.com/articles/how-calculate-jee-main-2019-rank-based-on-nta-percentile-score
Https://engineering.careers360.com/articles/jee-main-cutoff
For eligibilty of the JEE adavance you need get rank below 2,28,000 rank then you will be eligible
Regards
hope this helps
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