Hi dear,

You have got 85.5 percentile in JEE main that means your rank should be around 126006. However this is not your final rank. Your rank may vary if number of student in April month exam will increase. You can also calculate your rank as

Rank=(100-your percentile)×869010÷100

With this rank you have negligible chance to get any NIT. You can predict your college here

Hope it helps.

Ridhi, you can check your expected rank using the formula:

(100-your total percentile) x 869010/100

So with 85.5 percentile, your rank would be around 126006.

Also, if the number of students increases to 12 lakh in the April session, the formula for rank calculation would change to:

(100-your total percentile) x 1200000/100

Hence your expected rank in this case would be around 174000.

Now the cutoff percentile is expected to change every year depending on the number of seats available and the number of students appearing. While it is difficult to predict the exact qualifying cutoff, a percentile of 85 or above is decent enough to qualify for JEE Advanced. You can also go through the previous years' cutoff to get an idea. In 2019, the NTA score cutoff for the Common Rank List was 89.7548849

According to your percentile, you have a decent chance to clear the cutoffs for JEE Advanced. But it will be difficult to get a seat in CSE or any other branch in the top NITs or CFTIs. Although you can try for colleges through state level counselling.

I would suggest you to sit for the April session too and give your best in that exam so that your chance of qualifying JEE Mains and getting a top college increases. Solve the previous years' papers, brush up your concepts and revise thoroughly.

You can also go through our college predictor to check which colleges you are eligible for through your JEE Mains score. The link for the college predictor is:

All the best.