I got 86.57 percentile in JEE mains 2020 Jan 8th 2nd shift.what will be my rank?l m general category
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Hello Aspirant,
It would be difficult to tell you the exact about the qualifying cutoff & exact rank.
You may calculate your expected rank by this formula
100 - your total percentile score is the percentage of people ahead of you. 874469 are the number of candidates appeared for Jan exam. So rank formula is (100 - your total score) X 869010 /100. If the number of candidates for April exam increased to 1200000 then your final rank shall be (100 - your total score) X 1200000/100
Using the formula
(100 - your total score) X 869010 /100
Your probable rank will be 1,16,708.
This score seems enough to qualify the exam but chances seems less to get a seat in NITs, IIITs & GFTIs.
You can go for the state level counselling like Punjab, Haryana, Chandigarh Etc.
To know your admission possibilities in state level counselling, You can use JEE Main College Predictor tool given below.
I would also suggest you to appear for JEE Main 2020 April Session again if you wish to get admission in NITs, IIITs & GFTIs.
Good Luck!
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