I got 87.4 percentile in jee mains category sc hs karnataka male Will I get civil or mech in nit surathkal ?

Hi

With 87.4 percentile

• your rank will be around 128898 - 144900 as per our rank predictor at

  

  JEE Main Rank Predictor 2021 - Predict your JEE Main 2021 Rank, JEE Main Percentile Calculator

  JEE Main Rank Predictor - Know your expected IIT JEE Main 2021 Rank by using Careers360 JEE Main rank predictor tool based on JEE Mains scor ...

Your sc rank will be around 7000.

It is quite difficult to make prediction but yes as per past year trend ,

In 6th round of josaa counselling 2020, for sc category for gender neutral  closing rank to get a seat in NIT surathkal under home state is

• Civil engineering- 4681 sc rank

• Mechanical engineering - 3262

So, with your rank, you have low chance in NIT surathkal even under home state

You can check the same at

https://josaa.nic.in/Result/Result/currentorcr.aspx

But yes,

You  have chances in following NITs which are listed below along with their closing rank in 6th round of josaa counselling 2020, for sc category for gender neutral for other other state :-

• NIT Mizoram ,civil engineering :- 8376 sc rank

• National Institute of Technology, Andhra Pradesh, Metallurgical and Materials Engineering :- 8450 sc rank

• National Institute of Technology nagaland, Instrumentation Engineering :- 8641 sc rank

And a few more

This above prediction is on the past year data basis but  cut closing rank for colleges changes every year depending upon factors like number of candidates that write jee main examination, difficulty level of the question paper for different shifts of jee main etc so

To have a personalised report on your chances of getting a college you can go through our college predictor, it will give you complete list of colleges which you can get on the basis of the category you belong to,  your home state, your gender etc, the link for  jee main college predictor is provided below

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

Thankyou