I got 88.5200525 percentile in jee main 2020 in obc category. am I egibal to get any nit?
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Considering your percentile your rank can be calculated using the formula given below
(100-your total percentile)*869010/100
So in your case it will be
(100-88.52005)*869010/100= 99761
With such rank it is difficult to get seat in NIT.You may get seat through your category rank.Also you may qualify for JEE advanced.So you can prepare for JEE advanced if you want to get admission in IITs.But if you want to get admission in NITs you must prepare for JEE main April session.You can predict the college by using our college predictor
Hello dear student,
that is good percentile and you being student with reserved category there is a chance that you might get admission in NIT. And there is a probability that you are eligible to give JEE advanced also as your percentile is above 85. And roughly the students having percentile above 85 eligible to give JEE advanced. You can expect your rank in between 99,700-99,800
If in case you do not get admission in NIT then also you can get admission in good government colleges who consider the marks of JEE mains.
If you want to calculate your rank by your own then dear student you can do it as total percentile score is the percentage of people ahead of you. 869010 are the number of candidates appeared for Jan exam. So rank formula is (100 - your total score) X 869010 /100.
If the number of candidates for April exam increased to 1200000 then your final rank shall be (100 - your total score) X 1200000/100
Best wishes
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