JEE Main 2025: Rank Predictor | Admit Card Link | January Session Exam Analysis
JEE Main 2025: Memory Based Question: Jan 23 - Shift 1 | Shift 2 | Jan 22: Shift 1 | Shift 2
JEE Main 2025: High Scoring Topics | Sample Papers | Mock Tests | PYQs
You can calculate your rank in JEE Main Paper 2 using the formula:Rank = (100-percentile)*(No. of students appeared for the examination)/100.
As the no. of students appeared for Paper 2 (Jan) are around 112679, your rank will be around 12600. However as the no. of students in April changes, your rank will change according to that.
With this rank, there are very less chances of getting Architecture branch at NIT Calicut. As the closing cutoff rank for this branch is around 1200-1300 which is far away from your expected rank.
To check the list of all colleges which you may get with this percentile, kindly use the link provided below:
JEE Main Architecture/Paper-2 College Predictor - Know your college ad ...
For more information regarding the same, kindly use the B.Tech companion from the link given:
https://www.careers360.com/btech-companion
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